8. 解:
······································································································ 2分
········································································································· 3分
.···················································································································· 4分
當時,原式
.······································································ 6分
7. 解:(以下給出三種選擇方案,其他方案從略)
解答一:Y + Z =(3a2+3ab)+ (a2+ab)
=4a2+4ab
=4a(a+b).
解答二: X- Z = (2a2+3ab+b2)-(a2+ab)
=a2+2ab+b2 =(a+b)2.
解答三:Y- X=(3a2+3ab)- (2a2+3ab+b2)
=a2- b2 =(a+b)(a-b).
6. 解:原式==
5.
解:原式=4a2+4a+1-4a-2+3……………………………………………………3分
=4a2+2.…………………………………………………………………4分
當a=時,4a2+2=4×(
)2+2=10. …………………………………6分
4.
解:解:原式
將代入上式得
原式
3. 解:原式=
=
。
2. 解:原式·························································· 4分
·························································································································· 6分
當,
時,
原式···································································································· 8分
1.
68. (x-1)2
56. 57.
58.
59.
60.
或
61.
62.
63.
64. (a+2)(a-2) 65.
66.
67.
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