Question

9．計算：$\frac{1{2}^{0}-{3}^{2}×{6}^{-1}×{2}^{2}}{-{3}^{-2}}$×5^-1=9．

Answer 1

分析 $\frac{1{2}^{0}-{3}^{2}×{6}^{-1}×{2}^{2}}{-{3}^{-2}}$×5^-1=$\frac{1-9×\frac{1}{6}×4}{-\frac{1}{9}}$×$\frac{1}{5}$=$\frac{1-6}{-\frac{1}{9}}$×$\frac{1}{5}$=9，即可求得$\frac{1{2}^{0}-{3}^{2}×{6}^{-1}×{2}^{2}}{-{3}^{-2}}$×5^-1．

解答 解：$\frac{1{2}^{0}-{3}^{2}×{6}^{-1}×{2}^{2}}{-{3}^{-2}}$×5^-1=$\frac{1-9×\frac{1}{6}×4}{-\frac{1}{9}}$×$\frac{1}{5}$=$\frac{1-6}{-\frac{1}{9}}$×$\frac{1}{5}$=（-5）×（-9）×$\frac{1}{5}$=9，
∴$\frac{1{2}^{0}-{3}^{2}×{6}^{-1}×{2}^{2}}{-{3}^{-2}}$×5^-1=9，
故答案為：9．

點評 本題考查有理數指數冪的化簡求值，考查有理數冪的運算，考查計算能力，屬于基礎題．