Question

4．$\sqrt{2}$的倒數(shù)是$\frac{\sqrt{2}}{2}$，|2$\sqrt{3}$-3$\sqrt{2}$|=3$\sqrt{2}$-2$\sqrt{3}$，平方根等于它本身的數(shù)是0，1．

Answer 1

分析 根據(jù)倒數(shù)的定義，差的絕對(duì)值是大數(shù)減小數(shù)，平方的意義，可得答案．

解答 解：$\sqrt{2}$的倒數(shù)是 $\frac{\sqrt{2}}{2}$，|2$\sqrt{3}$-3$\sqrt{2}$|=3$\sqrt{2}$-2$\sqrt{3}$，平方根等于它本身的數(shù)是 0，1，
故答案為：$\frac{\sqrt{2}}{2}$，3$\sqrt{2}$-2$\sqrt{3}$，0，1．

點(diǎn)評(píng) 本題考查了實(shí)數(shù)的性質(zhì)，差的絕對(duì)值是大數(shù)減小數(shù)是解題關(guān)鍵．