Question

如圖，AB//CD,AE平分∠CAB, ∠C=80°,求∠AED的度數

Answer 1

解：∵AB//CD
∴∠C+ ∠CAB=180°
∵∠C=80°
∴∠CAB=180°-80°=100°
∵AE平分∠CAB
∴∠EAB=50°
∵AB//CD
∴∠EAB+∠AED=180°
∠AED=180°-50°=130°解析:
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