考點:奇數(shù)與偶數(shù)的初步認識,合數(shù)與質(zhì)數(shù)
專題:數(shù)的整除
分析:自然數(shù)中,是2的倍數(shù)的數(shù)叫做偶數(shù),不是2的倍數(shù)的數(shù)叫做奇數(shù);除了1和它本身以外,不含其它因數(shù)的數(shù)是質(zhì)數(shù);除了1和它本身外,還含有其它因數(shù)的數(shù)是合數(shù);據(jù)此解答即可.
解答:
解:根據(jù)偶數(shù)、合數(shù)的含義可知:2是偶數(shù),但2不是合數(shù),因為2只有1和它本身兩個因數(shù)是質(zhì)數(shù);
故答案為:×.
點評:本題考查了對偶數(shù)與合數(shù)的認識.解答此題應(yīng)根據(jù)偶數(shù)和合數(shù)的含義進行判斷.