題目列表(包括答案和解析)
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人體內葡萄糖的消耗為： C6H12O6(s)(葡萄糖)＋6O2(g) | |
| [ ] | |
A． |
806 g |
B． |
1000 g |
C． |
1250 g |
D． |
1 500 g |
25℃、101 kPa下，碳、氫氣、甲烷和葡萄糖的燃燒熱依次是393.5 kJ/mol、285.8 kJ/mol、890.3 kJ/mol、2800 kJ/mol，則下列熱化學方程式正確的是（ ）
A．C(s)+1/2 O2(g)＝CO(g) △H= ―393.5 kJ/mol
B．2H2(g)+O2(g)＝2H2O(l) △H= +571.6 kJ/mol
C．CH4(g)+2O2(g)＝CO2(g)+2H2O(g) △H= ―890.3 kJ/mol
D．C6H12O6(s) +6O2(g)＝6CO2(g)+6H2O(l) △H= ―2800 kJ/mol
25℃、101 kPa下，碳、氫氣、甲烷和葡萄糖的燃燒熱依次是393.5 kJ/mol、285.8 kJ/mol、890.3 kJ/mol、2800 kJ/mol，則下列熱化學方程式正確的是（ ）
| A．C(s)+1/2 O2(g)＝CO(g)△H=" ―393.5" kJ/mol |
| B．2H2(g)+O2(g)＝2H2O(l)△H="" +571.6 kJ/mol |
| C．CH4(g)+2O2(g)＝CO2(g)+2H2O(g)△H=" ―890.3" kJ/mol |
| D．C6H12O6(s) +6O2(g)＝6CO2(g)+6H2O(l)△H=" ―2800" kJ/mol |
25℃、101 kPa下，碳、氫氣、甲烷和葡萄糖的燃燒熱依次是393.5 kJ/mol、285.8 kJ/mol、890.3 kJ/mol、2800 kJ/mol，則下列熱化學方程式正確的是
| A．C(s)+1/2O2(g)＝CO(g) △H =" -" 393.5 kJ/mol |
| B．2H2(g)+O2(g)＝2H2O(l) △H =" +" 571.6 kJ/mol |
| C．CH4(g)+2O2(g)＝CO2(g)+2H2O(g) △H =" -" 890.3 kJ/mol |
| D．C6H12O6(s) +6O2(g)＝6CO2(g)+6H2O(l) △H =" -" 2800 kJ/mol |
25℃、101 kPa下，碳、氫氣、甲烷和葡萄糖的燃燒熱依次是393.5 kJ/mol、285.8 kJ/mol、890.3 kJ/mol、2800 kJ/mol，則下列熱化學方程式正確的是
A．C(s)+1/2O2(g)＝CO(g) △H = - 393.5 kJ/mol
B．2H2(g)+O2(g)＝2H2O(l) △H = + 571.6 kJ/mol
C．CH4(g)+2O2(g)＝CO2(g)+2H2O(g) △H = - 890.3 kJ/mol
D．C6H12O6(s) +6O2(g)＝6CO2(g)+6H2O(l) △H = - 2800 kJ/mol
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6CO2(g)＋6H2O(l) ΔH＝－2800 kJ·mol－1，如果某人每天消耗12540 kJ的熱量，則他每天至少要攝入葡萄糖的質量為