Question

若特稱命題“x∈R,使ax²+ax+1＜0”是假命題，則實數(shù)a的取值范圍是（　�。�

A.0≤a≤4

B.0＜a≤4

C.a≥0

D.a＞0

Answer 1

解析：即求“對x∈R,使ax²+ax+1≥0”是真命題,a=0時,1≥0成立,a＞0時,Δ=a²-4a≤0,?

∴0＜a≤4,故0≤a≤4.故選A.

答案：A