Question

如圖所示的△ABC為等邊三角形，邊長為2，D為BC中點，△ADC繞點A順時針旋轉60°得到△AEB，則BE=_▲__.

 

Answer 1

1

解析:∵△ABC為等邊三角形，且△ABC邊長為2cm，∴∠ACB=60°，

∵△ADC繞點A順時針旋轉60°得到△AEB，∴∠ABE=∠ACB=60°，∴BE=DC=1cm，