Question

計(jì)算：(

x-2

x2+2x

-

x+1

x2+4x+4

)÷

x+4

x

．

Answer 1

分析：首先把括號(hào)里的式子進(jìn)行通分，然后把除法運(yùn)算轉(zhuǎn)化成乘法運(yùn)算，進(jìn)行約分化簡(jiǎn)．

解答：解：原式=（

x2-4

x(x+2)2

-

x2+x

x(x+2)2

）•

x

x+4

=

-(x+4)

x(x+2)2

•

x

x+4

=-

1

(x+2)2

．

點(diǎn)評(píng)：本題主要考查分式的混合運(yùn)算，通分、因式分解和約分是解答的關(guān)鍵．