Question

現(xiàn)有200g稀硫酸跟足量的鋅完全反應(yīng)后，生成氣體0.2g，求則參加反應(yīng)的鋅的質(zhì)量為多少克？，所得溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)為多少？

Answer 1

設(shè)參加反應(yīng)的鋅的質(zhì)量為x，生成硫酸鋅的質(zhì)量為y．
Zn+H₂SO₄=ZnSO₄+H₂↑
65       161   2
x        y     0.2g

65

2

=

x

0.2g

      x=6.5g

161

2

=

y

0.2g

     y=16.1g
反應(yīng)后溶液的質(zhì)量：6.5g+200g-0.2g=206.3g
反應(yīng)所得溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)=

16.1g

206.3g

×100%=7.8%
答：參加反應(yīng)得鋅的質(zhì)量為6.5g，所得溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)為7.8%．