Question

某硝酸銨化肥的外包裝如圖6，推算該袋化肥的純度．

Answer 1

分析：由某硝酸銨化肥的外包裝袋圖，先計算出純凈硝酸銨中氮元素的質(zhì)量分數(shù)，根據(jù)混合物中某化合物的質(zhì)量分數(shù)=

含雜質(zhì)物質(zhì)元素的質(zhì)量分數(shù)

物質(zhì)中某元素的質(zhì)量分數(shù)

×100%，進行分析解答．

解答：解：純凈硝酸銨中氮元素的質(zhì)量分數(shù)=

14×2

14+1×4+14+16×3

×100%=35%．
該袋化肥中NH₄NO₃的質(zhì)量分數(shù)為

34.3%

35%

×100%=98%．
答：該袋化肥中硝酸銨的質(zhì)量分數(shù)為98%．

點評：本題有一定難度，掌握混合物中某化合物的質(zhì)量分數(shù)=

含雜質(zhì)物質(zhì)元素的質(zhì)量分數(shù)

物質(zhì)中某元素的質(zhì)量分數(shù)

×100%是正確解答本題的關鍵．