解:①[4

-(

+1

×2)]÷2

=[4

-

-3

]÷2

,
=

×

,
=

;
②0.68×

-

×

+

×68%
=0.68×

-

×0.68+

×0.68,
=(

-

+

)×0.68,
=1×0.68,
=0.68;
③[1

+2

×(2

-2.375)]×

÷7

,
=[

+2

×(2.375-2.375)]×

×

,
=[

+2

×0]×

×

,
=

×

×

,
=

;
④10.45÷[(7

-1

)×1.8-0.65÷2

]
=10.45÷[5

×1.8-0.65×

],
=10.45÷[10.75-0.3],
=10.45÷10.45,
=1.
分析:算式①可根據(jù)一個(gè)數(shù)減兩個(gè)數(shù)的和,等于用這個(gè)數(shù)分別減去兩個(gè)數(shù)的減法性質(zhì)計(jì)算;
算式②可根據(jù)乘法分配律計(jì)算;
算式③④根據(jù)四則混合運(yùn)算的運(yùn)算順序計(jì)算即可:先算乘除,再算加減,有括號的要先算括號里面的.
點(diǎn)評:當(dāng)算式中同時(shí)含有分?jǐn)?shù)與小數(shù)時(shí),要根據(jù)式中數(shù)據(jù)的特點(diǎn)靈活將它們互化后再進(jìn)行計(jì)算.