
如圖,在直角坐標(biāo)系中,O為原點(diǎn).點(diǎn)A在x軸的正半軸上,點(diǎn)B在y軸的正半軸上,tan∠OAB=2.二次函數(shù)y=x
2+mx+2的圖象經(jīng)過點(diǎn)A,B,頂點(diǎn)為D.
(1)求這個(gè)二次函數(shù)的解析式;
(2)將△OAB繞點(diǎn)A順時(shí)針旋轉(zhuǎn)90°后,點(diǎn)B落到點(diǎn)C的位置.將上述二次函數(shù)圖象沿y軸向上或向下平移后經(jīng)過點(diǎn)C.請直接寫出點(diǎn)C的坐標(biāo)和平移后所得圖象的函數(shù)解析式;
(3)設(shè)(2)中平移后所得二次函數(shù)圖象與y軸的交點(diǎn)為B
1,頂點(diǎn)為D
1.點(diǎn)P在平移后的二次函數(shù)圖象上,且滿足△PBB
1的面積是△PDD
1面積的2倍,求點(diǎn)P的坐標(biāo).