Question

已知sin(π－α)＝log₈，且α∈，則tan(2π－α)的值為________．

Answer 1

sin(π－α)＝sin α＝log₈＝－，
又α ∈，
得cos α＝＝，
tan(2π－α)＝tan(－α)＝－tan α＝－＝.