Question

若復(fù)數(shù)z滿足iz=-2+3i（i是虛數(shù)單位），則復(fù)數(shù)z=

3+2i

．

Answer 1

分析：根據(jù)復(fù)數(shù)z滿足iz=-2+3i，可得 z=

-2+3i

i

，利用兩個(gè)復(fù)數(shù)代數(shù)形式的除法法則，求出復(fù)數(shù)z．

解答：解：∵復(fù)數(shù)z滿足iz=-2+3i，∴z=

-2+3i

i

=

(-2+3i)(-i)

-i2

=3+2i，
故答案為：3+2i．

點(diǎn)評(píng)：本題主要考查兩個(gè)復(fù)數(shù)代數(shù)形式的除法，兩個(gè)復(fù)數(shù)相除，分子和分母同時(shí)乘以分母的共軛復(fù)數(shù)．