Question

已知點P(x₀,y₀)在直線l:Ax+By+C=0上，則直線l的方程一定可以表示為(    )

A.A(x+x₀)+B(y+y₀)+C=0                    B.A(x-x₀)+B(y-y₀)+C=0

C.A(x+x₀)+B(y+y₀)=0                         D.A(x-x₀)+B(y-y₀)=0

Answer 1

D

解析：∵Ax₀+By₀+C=0,∴C=-(Ax₀+By₀).

∴Ax+By+C=Ax+By-(Ax₀+By₀)=0,即A(x-x₀)+B(y-y₀)=0.