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【題目】有兩只電壓表V1和V2,量程已知,電阻未知。另有一干電池,它的內阻不能忽略,但不知等于多少,其電動勢數值不超出電壓表的量程,干電池不許拆開。現給你上述兩只電壓表、一個開關S和若干導線,請設計一個測量上述干電池電動勢E的實驗方案。

1畫出測量電路圖。

2實驗中應測定的物理量是:________。

3以測得的物理量為已知量,導出計算干電池電動勢的公式E=________。

【答案】1如圖

2S閉合時電壓表V1的示數U1

S斷開時電壓表V1、V2的示數U1′、U2

3

【解析】1電路圖如下

2S閉合時,V1示數為U1;S斷開時,V1、V2的示數分別為U1′和U2′。

3設V1表的內電阻為RV,由閉合電路歐姆定律

E=U1r,E=U1′+U2′+r

解得:E=

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