(1)

(2)

(3)

(4)

(5)

(6)

解析:
(1) 解:將②代入①得




···································· 2分
將

代入②得

························· 4分
∴

是原方程組的解··························· 5分
(2) 解:①+②得


···································· 2分
將

代入①得



···································· 4分
∴

是原方程組的解··························· 5分
(3) 解:②-①得



···································· 2分
將

代入①得



∴

是原方程組的解··························· 5分
(4) 解:原方程組變形為

···················· 1分由①得

③
由②得

④
③+④得
x =" 8···························" 3分
將
x = 8代入④得
y =" 1····························" 4分
∴

是原方程組的解···························· 5分
(5) 解:由①得


③································ 1分
由②得


④································ 2分
③×2得

⑤
④×3得

⑥
⑤-⑥得


····································· 3分
將
y = 1代入④得


····································· 4分
∴

是原方程組的解···························· 5分
(6) 解:①+②得


③·································· 1分
①-②得


④·································· 2分
③+④得


····································· 3分
將

代入③得
y =" –" 2 ··························· 4分
∴

是原方程組的解 5分