Question

指出3x²-8x+2x³-1是幾次幾項(xiàng)式．并說(shuō)出一次項(xiàng)及二次項(xiàng)的系數(shù)，并將多項(xiàng)式按x的升冪排列．

Answer 1

分析：根據(jù)多項(xiàng)式是由幾個(gè)單項(xiàng)式的和構(gòu)成，根據(jù)項(xiàng)與系數(shù)概念找出一次項(xiàng)及二次項(xiàng)的系數(shù)，按照x的升冪排列即可．

解答：解：3x²-8x+2x³-1是三次四項(xiàng)式．一次項(xiàng)系數(shù)為-8，二次項(xiàng)的系數(shù)為3，將多項(xiàng)式按x的升冪排列為2x³+3x²-8x-1．

點(diǎn)評(píng)：此題考查了多項(xiàng)式，熟練掌握多項(xiàng)式的定義是解本題的關(guān)鍵．