Question

（2012•西藏）計(jì)算：(

1

2

)-1+2cos30°+|-3|-

3

(2012-π)0．

Answer 1

分析：分別根據(jù)特殊角的三角函數(shù)值、0指數(shù)冪、負(fù)整數(shù)指數(shù)冪及絕對(duì)值的性質(zhì)計(jì)算出各數(shù)，再根據(jù)實(shí)數(shù)混合運(yùn)算的法則

解答：解：原式=2+2×

3

2

+3-

3

=2+

3

+3-

3

=5．

點(diǎn)評(píng)：本題考查的是實(shí)數(shù)的運(yùn)算，熟記0指數(shù)冪、負(fù)整數(shù)指數(shù)冪、絕對(duì)值的性質(zhì)及特殊角的三角函數(shù)值是解答此題的關(guān)鍵．